If the current loser is equal to the original winner , a loop is closed. Return true .
: Every possible matchup was listed. Alice vs. Bob, Bob vs. Charlie, Charlie vs. Alice.
You can write a helper function, such as bool has_cycle(int winner, int loser) .
If any recursive call returns true , pass true all the way up. If you check all paths and find no loop, return false . Best Practices and Debugging Tips Cs50 Tideman Solution
This function is identical to the one in plurality. It should record the voter’s rank for each candidate.
The Tideman method works by constructing a directed graph of candidates:
Calculate the strength of victory for a pair as preferences[pair.winner][pair.loser] . Use a sorting algorithm (like Selection Sort or Bubble Sort) to arrange the pairs array so the pair with the highest strength comes first. 5. lock_pairs If the current loser is equal to the
Before locking edges into the graph, you must sort the pairs so the strongest victories are processed first.
Once a voter's ranks are established, the record_preferences function updates the global preferences matrix.
To successfully write the solution, you must complete six specific functions inside the provided CS50 distribution code. 1. vote Alice vs
for (int j = 0; j < candidate_count; j++)
function. Its goal is to create a directed acyclic graph (DAG) by locking pairs of candidates in order of their strength of victory, provided that locking a pair does not create a cycle. The Core Logic: lock_pairs
void record_preferences(int ranks[]) for (int i = 0; i < candidate_count; i++) for (int j = i + 1; j < candidate_count; j++) preferences[ranks[i]][ranks[j]]++; Use code with caution. 3. add_pairs
If a voter ranks candidate A higher than candidate B, increment preferences[A][B] .